Joseph jogs from one end a to the other end b
NettetJoseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. … Nettet6. aug. 2024 · Answer: Explanation: (a) It is given that Joseph jogs on a straight road of 300m in a time interval of 2 minutes and 30 seconds, which is equal to 150seconds. …
Joseph jogs from one end a to the other end b
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NettetJoseph jogs from one end A to the other end B of a straight300 m road in 2 minutes 30 seconds and th - YouTube 0:00 / 15:43 #class9 #motion Joseph jogs from one end A … Nettet7. mai 2024 · Q2 ) Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in ...
NettetJoseph jogs from one end A to the other end B of a straight m road in 300 2 min 30 s and then turns around and jogs 100 m back to point C in another 1 min. ... Class- IX-CBSE-Science Motion. Practice more on Motion Page - 2 www.embibe.com. Solution: (a) From end A to end B. Distance covered by Joseph while jogging from A to B = 300 m … Nettet2. apr. 2024 · #class9#motion#JosephjogsfromoneendAtotheotherendBofastraight300mroadin2minutes30secondsandthenturnsaroundandjogs100mbacktopointCinanother1minuteWhatareJosep...
Netteta) when he jogs from A to B on a straight road, displacement = distance = 300m time = 2 minutes 30 seconds = 150 s velocity = 300/150 = 2 m/s speed = 300/150 = 2m/s … NettetJoseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. ... = 400m/210s = 1.9 m/s. Displacement from A to B to C = (300-100) m = 200 m. Total time taken = 210 s. Average velocity = Displacement/Total time
NettetClick here👆to get an answer to your question ️ Joseph jogs from one end A to the other end B of the straight 300 m road in 2 minutes 50 seconds and then turns around and jogs 100 m back to point C in another 1 minutes. Joseph's average speeds and velocities in jogging, between points A and B, respectively, will be
NettetBest Answer. Distance covered from point A to point C = 300m + 100m = 400 meters. Time taken to travel from point A to point B = 2 minutes and 30 seconds = 150 seconds. Time taken to travel from point A to point C = 2 min 30 secs + 1 min = 210 seconds. Therefore, the average speed while traveling from A to B = 300/150 ms-1 = 2 m/s. charlies fine food companyNettetThe average speed and average velocity of Joseph from A to B are the same and equal to 2 m/s. (b) From end A to end C. Total distance covered = Distance from A to B + … charlies flat bookingNettet10. jun. 2016 · Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in … charlies fine food spartanburgNettet22. mar. 2024 · Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. ... The displacement and the time taken of Joseph is same ingoing from A to B i.e., 300m and 150 s respectively. Therefore, Average velocity ... charlies fish and chip shop truroNettet15. aug. 2024 · Solution For (iv) Average velocity =t7π =20000 =25 m/min( along AD ) Example 3.13 Joseph jogs from one end A to the other end B of a straight 300 m road in 2 min50 s and then turns around and jogs 100. Solution For (iv) Average velocity =t7π =20000 =25 m/min ( along AD ... charlies favourite bookNettetJoseph Jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and t - YouTube Hello Friends in this video I am going to solve the following … charlies flatNettet10. jul. 2024 · 2. Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in ano... hartington creamery shop