WebQuestion: (20 pts) Compute the quantity of five-digit positive numbers that are divisible by (a) (i) 13 (ii) 15 (iii) 17 (b) 13, 15, and 17 (c) 13, 15, or 17 (Inclusive Or) (d) 13 and 15, but not 17 (20 pts) Compute the quantity of five-digit positive numbers that are divisible by
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WebAdded 20 to each number. 5. 250,280, 300, 310, 330. 25. Draw a star if the number is divisible by 2,a square if it is divisible by 5 and triangle if it is divisible by 10 … WebApr 5, 2024 · In the first part of the question, we have to find the greatest number of 5 digits exactly divisible by 12, 15 and 36. For that, we will find the L.C.M of 12, 15 and 36. We …
WebMar 11, 2024 · But 9900 is not a five-digit number. So, the next number which is divisible by 495 will be (9900 + 495) = 10395. So, the smallest five-digit number divisible by 495 (i.e. LCM of 15, 55 and 99) is equal to 10395. Hence, the smallest five-digit number divisible by 15, 55 and 99 will be 10395. Note: Whenever we face such a question … WebNov 14, 2024 · We know that 15 is a product of 5 and 3 i.e. 5B5B5 is divisible by 5 because it ends with 5. So, for a number of this format to be divisible by 15, it must be divisible by 3 Numbers in this category are: 50505, 53535, 56565 and 59595 Hence, there are 4 five-digit flippy numbers divisible by 5. Advertisement Advertisement
WebApr 7, 2024 · A number is divisible by 15 if it is divisible by 5 (if the last digit is 5 or 0), and it is divisible by 3 (if sum of digits is divisible by 3). Here, used accumulate function to sum up all the numbers. C++ Java Python3 C# PHP Javascript #include using namespace std; bool isDivisible (string s) { int n = s.length (); WebFind the greatest number of five digits, which is exactly divisible by 7, 10, 15, 21 and 28. What is the least number that should be multiplied to 100! to make it perfectly divisible …
WebJan 5, 2024 · If a number is divisible by 12, 18, 30. Then it should be a multiple of LCM of 12, 15 and 18. Now, LCM of 12, 15 and 18 = 2 × 2 × 3 × 3 × 5=180. The smallest 5-digits number is 10000. Now, divide it by 180. We get a quotient 55 remainder is 100. If we add 80 to it then it will be completely divided by 180 with a quotient 56. Therefore, 180 ...
WebTo test the divisibility of a number by a power of 2 or a power of 5 (2 n or 5 n, in which n is a positive integer), one only need to look at the last n digits of that number. To test divisibility by any number expressed as the product of prime factors , we can separately test for divisibility by each prime to its appropriate power. canning raspberriesWebApr 11, 2024 · Input : N = 5115 Output : YES Explanation: 5115 is divisible by both 1 and 5. So print YES. Input : 27 Output : NO Explanation: 27 is not divisible by 2 or 7. Recommended: Please try your approach on {IDE} first, before moving on to the solution. Approach: The idea to solve the problem is to extract the digits of the number one by … canning ratesWebJun 4, 2024 · Since question is a bit vague in exact requirement, I will write the basic logic that can find the numbers exactly divisible by other number. There is something called modulus (%) operator. It gives you the remainder of division.e.g. 11%5 will be 1, 13%5 will be 3, whereas 15%5 will be 0 so logic goes like, fixtradingcommunity.orgWebFind the greatest number of five digits, which is exactly divisible by 7, 10, 15, 21 and 28. What is the least number that should be multiplied to 100! to make it perfectly divisible by 350? Interview Categories: canning raspberries water bathWebNow, 15=3×5. 25=5×5. 40=2×2×2×5. and 75=3×5×5. L.C.M. of 15,25,40 and 75 is 2×2×2×3×5×5=600. On dividing 9999 by 600, the remainder is 399. fix track lightingWebJul 17, 2024 · "5 digit number" which is divisible by 12, 15 and 36. Answer: First find the LCM (12, 15, & 36) LCM . 99999 is the biggest five digit number. We can find the remainder when 99999 is divided by 180. Thus . Therefore, 99 is the remainder when 99999 is divided by 1870. Subtract the remainder 99 from 99999 will get the 99900. Hence, … canning raspberry jam recipe with lemonWebA number is divisible by 2 if the last digit (unit) is divisible by 2 or is a multiple of 2, i.e. 0, 2, 4, 6, and 8. A number that is divisible by 2 is also called an even number. There are actually many ways to determine if 238 is divisible by 2. The Even Number Method. If 238 is even, then it is divisible by 2. 238 is even, so 238 is ... canning raspberry jam